Feel like using the left side of your brain today? If so, I have something just for you. I recently stumbled upon this math problem that uses escalators as an example. So, I thought that I would pose the problem to our readers. Let’s see how well you studied in school! You can find the answer and explanation here but give us your answer in the comments section first, then take a peek.

A and B walk up an escalator. The escalator moves at a constant speed. A takes six steps for every four of B’s step. A gets to the top of the escalator after having taken 50 steps , while B( Slower) takes only 40 steps to reach the top. If the escalator were turned off, how many steps would they have to take to walk up?

a. 80

b. 100

c. 120

d. 160

So, what do you think?

All of them

since B has taken 40 steps if they had travelled for same time A would have taken 60 stepss [6:4] but A has taken only 50 steps here so A has travelled for 5/6th time of B

Both reach end of escalator so

50 + S*5/6t = 40 +S *t [where s = speed of escalator and t is time]

so 1/6St =10

St =60

so steps = 40+St = 40 +60 = 100!!!!

Oooh…………………..great question but also complicated………….but I think 100 is right answer

Nice

Answer is b ) 100